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2x^2-41.2x=50
We move all terms to the left:
2x^2-41.2x-(50)=0
a = 2; b = -41.2; c = -50;
Δ = b2-4ac
Δ = -41.22-4·2·(-50)
Δ = 2097.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41.2)-\sqrt{2097.44}}{2*2}=\frac{41.2-\sqrt{2097.44}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41.2)+\sqrt{2097.44}}{2*2}=\frac{41.2+\sqrt{2097.44}}{4} $
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